Invoke method with parameter type int : Parameter « Reflection « C# / CSharp Tutorial

1. C# / CSharp Tutorial
2. Reflection
3. Parameter

using System; 
using System.Reflection; 
 
class MyClass { 
  public MyClass(int i) { 
    Console.WriteLine("Constructing MyClass(int). "); 
  } 
 
  public MyClass(int i, int j) { 
    Console.WriteLine("Constructing MyClass(int, int). "); 
  } 
 
  public int sum() { 
    return 0; 
  } 
 
  public bool isBetween(int i) { 
    return false; 
  } 
 
  public void set(int a, int b) { 
    Console.Write("Inside set(int, int). "); 
  } 
 
  public void set(double a, double b) { 
    Console.Write("Inside set(double, double). "); 
  } 
 
  public void show() { 
    Console.WriteLine("Values"); 
  } 
} 
 
class MainClass { 
  public static void Main() { 
    Type t = typeof(MyClass); 
    int x; 

    // Find matching constructor. 
    ConstructorInfo[] ci = t.GetConstructors(); 
 
    for(x=0; x < ci.Length; x++) { 
      ParameterInfo[] pi =  ci[x].GetParameters(); 
      if(pi.Length == 2) break; 
    } 
 
    if(x == ci.Length) { 
      Console.WriteLine("No matching constructor found."); 
      return; 
    } 
    else 
      Console.WriteLine("Two-parameter constructor found.\n"); 



    // Construct the object.   
    object[] consargs = new object[2]; 
    consargs[0] = 10; 
    consargs[1] = 20; 
    object reflectOb = ci[x].Invoke(consargs);  
  } 
}

Two-parameter constructor found.

Constructing MyClass(int, int).