new Regex((abc)*)x(\1) : Regular Expression « Regular Expression « C# / CSharp Tutorial






using System;
using System.Collections.Generic;
using System.Globalization;
using System.Text;
using System.Text.RegularExpressions;
using System.Reflection;

public class MainClass{

   public static void Main(){
        Regex r1 = new Regex(@"((abc)*)x(\1)");
        string s1 = "abcabcabcxabc";
        Console.WriteLine(r1.IsMatch(s1) + "..." + r1.Match(s1).Value);
   }
}
True...abcxabc








17.1.Regular Expression
17.1.1.Use Regular Expressions to split string
17.1.2.Do a replace using the Regex
17.1.3.Reverse
17.1.4.Regular Expresion Part
17.1.5.new Regex('^\\d+') 1
17.1.6.new Regex('\d+$') 2
17.1.7.new Regex('^\\d+$') 3
17.1.8.new Regex('(abc)|(xyz)*') 1
17.1.9.new Regex('((abc)|(xyz))*') 2
17.1.10.new Regex('((?:abc)|(?:xyz))*') 3
17.1.11.new Regex(?(^\d)^\d+$|^\D+$)
17.1.12.new Regex((abc)*)x(\1)
17.1.13.new Regex(^\d+$\n+, RegexOptions.Multiline)
17.1.14.new Regex((abc)*abc((abcd)|z)bc)
17.1.15.new Regex(<[^>]+>[^<]*]+>): for XML tag
17.1.16.new Regex(<([^>]+)>[^<]*: for XML tag
17.1.17.Using RegEx