converts the Integer to a String representation of the same column.
Sub Main() Debug.Print GetColumnRef(3) End Sub Function GetColumnRef(columnIndex As Integer) As String Dim numAlpha As Integer Dim firstLetter As String Dim secondLetter As String Dim remainder As Integer numAlpha = columnIndex \ 26 Select Case columnIndex / 26 Case Is <= 1 'Column ref is between A and Z firstLetter = Chr(columnIndex + 64) GetColumnRef = firstLetter Case Else 'Column ref has two letters remainder = columnIndex - 26 * (columnIndex \ 26) If remainder = 0 Then firstLetter = Chr(64 + (columnIndex \ 26) - 1) secondLetter = "Z" GetColumnRef = firstLetter & secondLetter Else firstLetter = Chr(64 + (columnIndex \ 26)) secondLetter = Chr(64 + remainder) GetColumnRef = firstLetter & secondLetter End If End Select End Function