'%' is for any length of letters
1> CREATE TABLE employee (emp_no INTEGER NOT NULL,
2> emp_fname CHAR(20) NOT NULL,
3> emp_lname CHAR(20) NOT NULL,
4> dept_no CHAR(4) NULL)
5> GO
1>
2> insert into employee values(1, 'Matthew', 'Smith', 'd3')
3> insert into employee values(2, 'Ann', 'Jones', 'd3')
4> insert into employee values(3, 'John', 'Barrimore','d1')
5> insert into employee values(4, 'James', 'James', 'd2')
6> insert into employee values(5, 'Elsa', 'Bertoni', 'd2')
7> insert into employee values(6, 'Elke', 'Hansel', 'd2')
8> insert into employee values(7, 'Sybill', 'Moser', 'd1')
9> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> select * from employee
3> GO
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
4 James James d2
5 Elsa Bertoni d2
6 Elke Hansel d2
7 Sybill Moser d1
(7 rows affected)
1>
2>
3> -- LIKE Operator
4>
5> SELECT emp_fname, emp_lname, emp_no FROM employee WHERE emp_lname LIKE 'J%'
6> GO
emp_fname emp_lname emp_no
-------------------- -------------------- -----------
Ann Jones 2
James James 4
(2 rows affected)
1> drop table employee
2> GO
1>
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