DATENAME(month, '4-29-1988') returns a string containing the descriptive name


1>
2> SELECT DATENAME(month, '4-29-1988')
3> GO

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April

(1 rows affected)
1>
2>

1.	DATENAME returns the part of the date in a literal form.
2.	Using the DATENAME() Function
3.	Find out the month name in two months time
4.	DATENAME: return the part of the date in a literal form
5.	select DATENAME(day, '2002-09-30 11:35:00')
6.	select DATENAME(year, '2002-09-30 11:35:00')
7.	select DATENAME(hour, '2002-09-30 11:35:00')
8.	select DATENAME(minute, '2002-09-30 11:35:00')
9.	select DATENAME(second, '2002-09-30 11:35:00')
10.	select DATENAME(quarter, '2002-09-30 11:35:00')
11.	select DATENAME(dayofyear, '2002-09-30 11:35:00')
12.	select DATENAME(week, '2002-09-30 11:35:00')
13.	select DATENAME(weekday, '2002-09-30 11:35:00')

DATENAME(month, '4-29-1988') returns a string containing the descriptive name : DATENAME « Date Timezone « SQL Server / T-SQL