DATEADD(second, 9000, '4-29-1988 10:30 AM'): 9,000 seconds after
1> -- 9,000 seconds after:
2>
3> SELECT DATEADD(second, 9000, '4-29-1988 10:30 AM')
4> GO
-----------------------
1988-04-29 13:00:00.000
(1 rows affected)
1>
Related examples in the same category
1. | DATEADD: add or subtract a number of days, months, or years from a specific date | | |
2. | SELECT DATEADD(yy,12,"24 March 1964"): Add 12 years to 24th March 1964 | | |
3. | SELECT DATEADD(m,12,"24 March 1964"): Add 12 months to 24th March 1964 | | |
4. | SELECT DATEADD(wk,12,"24 March 1964"): Add 12 weeks to 24th March 1964 | | |
5. | SELECT DATEADD(hh,12,"24 March 1964"): Add 12 hours to 24th March 1964 | | |
6. | Add 12 minutes to 24th March 1964 | | |
7. | DATEADD(Day, 90, '4-29-1988'): adds a specific number of date unit intervals to a date/time value | | |
8. | DATEADD(year, 18, '4-29-1988 10:30 AM'): 18 years later | | |
9. | DATEADD(yy, -18, '4-29-1988 10:30 AM'): 18 years before | | |
10. | DATEADD(mi, -9000000, '4-29-1988 10:30 AM'): 9,000,000 milliseconds before | | |
11. | SELECT DATEADD(dayofyear, 18, '4-29-1988 10:30 AM') | | |
12. | SELECT DATEADD(quarter, 18, '4-29-1988 10:30 AM') | | |
13. | Combine the CONVERT()and the DATEADD() functions to format a return
date value nine months before September 8, 1989 | | |
14. | SELECT DATEADD(mi, -30, '2005-09-01 23:30:00.000') | | |
15. | select DATEADD(month, -1, '2002-09-30 11:35:00') | | |
16. | DATEADD: add days to a date | | |
17. | Combine DateADD and DateDIFF to get the last date of a month | | |