Declare variable in varchar type
1> -- DIFFERENCE: work out when one string sounds similar to another string.
2>
3> -- '0' means that the two strings aren't even close,
4> -- '4' means a perfect match
5>
6> DECLARE @s1 varchar(6)
7> DECLARE @s2 varchar(6)
8> SET @s1 = "Dewson"
9> SET @s2 = "Joosun"
10>
11> SELECT DIFFERENCE(@s1,@s2)
12> GO
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3
(1 rows affected)
1>
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