Use the CONCAT() and LEFT() functions to create registration codes for the employees.

      
mysql>
mysql> CREATE TABLE Employees
    -> (
    ->     EmpID SMALLINT NOT NULL AUTO_INCREMENT PRIMARY KEY,
    ->     EmpFN VARCHAR(20) NOT NULL,
    ->     EmpMN VARCHAR(20) NULL,
    ->     EmpLN VARCHAR(20) NOT NULL
    -> )
    -> ENGINE=INNODB;
Query OK, 0 rows affected (0.01 sec)

mysql>
mysql> # insert 7 records into the "employees" table
mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Arthur", "Smith","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Peter", "Jones","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Ann", "Smith","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Sandra", "Williams","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Andrew", "Smith","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Paul", "Jones","A");
Query OK, 1 row affected (0.00 sec)

mysql> INSERT INTO employees (EmpFN, EmpLN, EmpMN) VALUES ("Sally", "Williams","A");
Query OK, 1 row affected (0.00 sec)

mysql>
mysql>
mysql> SELECT EmpID, CONCAT(LEFT(EmpFN, 2), LEFT(EmpLN, 3), EmpID) AS RegID
    -> FROM Employees
    -> ORDER BY EmpID;
+-------+--------+
| EmpID | RegID  |
+-------+--------+
|     1 | ArSmi1 |
|     2 | PeJon2 |
|     3 | AnSmi3 |
|     4 | SaWil4 |
|     5 | AnSmi5 |
|     6 | PaJon6 |
|     7 | SaWil7 |
+-------+--------+
7 rows in set (0.00 sec)

mysql>
mysql> drop table Employees;
Query OK, 0 rows affected (0.00 sec)

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Use the CONCAT() and LEFT() functions to create registration codes for the employees. : CONCAT « String « SQL / MySQL

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