String contains : Contains « Regular Expression « SQL / MySQL

1. SQL / MySQL
2. Regular Expression
3. Contains

String contains

    
/*

mysql> select * from Bird;
+----------+-------+---------+------+------------+------------+
| name     | owner | species | sex  | birth      | death      |
+----------+-------+---------+------+------------+------------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL       |
| RedBird  | Yin   | Bus     | m    | 1979-04-30 | 0000-00-00 |
| RedBird  | Yin   | Bus     | m    | 1998-01-30 | NULL       |
+----------+-------+---------+------+------------+------------+
3 rows in set (0.00 sec)

mysql> /*names containing a 'u'*/
mysql> SELECT * FROM Bird WHERE name LIKE '%u%';
+----------+-------+---------+------+------------+-------+
| name     | owner | species | sex  | birth      | death |
+----------+-------+---------+------+------------+-------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL  |
+----------+-------+---------+------+------------+-------+
1 row in set (0.01 sec)


*/  
Drop table Bird;

CREATE TABLE Bird (
    name VARCHAR(20), 
    owner VARCHAR(20),
    species VARCHAR(20), 
    sex CHAR(1), 
    birth DATE, 
    death DATE
);
  
INSERT INTO  Bird VALUES ('BlueBird','Joe','Car','f','1999-03-30',NULL);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1979-04-30',1998-01-30);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1998-01-30',NULL);
  
select * from Bird;

/*names containing a 'u'*/

SELECT * FROM Bird WHERE name LIKE '%u%';

  

           
         
    
    
    
  

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