Pattern Matching: beginning with 'b' : Begin With « Regular Expression « SQL / MySQL






  1. SQL / MySQL
  2. Regular Expression
  3. Begin With

Pattern Matching: beginning with 'b'

    
/*

mysql> select * from Bird;
+----------+-------+---------+------+------------+------------+
| name     | owner | species | sex  | birth      | death      |
+----------+-------+---------+------+------------+------------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL       |
| RedBird  | Yin   | Bus     | m    | 1979-04-30 | 0000-00-00 |
| RedBird  | Yin   | Bus     | m    | 1998-01-30 | NULL       |
+----------+-------+---------+------+------------+------------+
3 rows in set (0.00 sec)

mysql> SELECT * FROM Bird WHERE name LIKE 'B%';
+----------+-------+---------+------+------------+-------+
| name     | owner | species | sex  | birth      | death |
+----------+-------+---------+------+------------+-------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL  |
+----------+-------+---------+------+------------+-------+
1 row in set (0.00 sec)


*/  
  
Drop table Bird;

CREATE TABLE Bird (
    name VARCHAR(20), 
    owner VARCHAR(20),
    species VARCHAR(20), 
    sex CHAR(1), 
    birth DATE, 
    death DATE
);
  
INSERT INTO  Bird VALUES ('BlueBird','Joe','Car','f','1999-03-30',NULL);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1979-04-30',1998-01-30);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1998-01-30',NULL);
  
select * from Bird;

SELECT * FROM Bird WHERE name LIKE 'B%';








Related examples in the same category

1.The caret (^) anchors the start, and the dollar sign ($) the end;
2.String begins with
3.Pattern match: string begin with a certain letter
4.Pattern match: string begin and end
5.Show records where the name begins with a "B"
6.Show records where the name begins with a "B" or "C"
7.Strings that begin with a particular substring:
8.Matches strings that begin with a vowel or end with er:
9.Matches where a is the first character