February 29 of leap years and March 1 of non-leap years appear to be the same day: : Year « Date Time « SQL / MySQL
- SQL / MySQL
- Date Time
- Year
February 29 of leap years and March 1 of non-leap years appear to be the same day:
mysql>
mysql>
mysql> SELECT DAYOFYEAR('1996-02-29'), DAYOFYEAR('1997-03-01');
+-------------------------+-------------------------+
| DAYOFYEAR('1996-02-29') | DAYOFYEAR('1997-03-01') |
+-------------------------+-------------------------+
| 60 | 60 |
+-------------------------+-------------------------+
1 row in set (0.00 sec)
mysql>
Related examples in the same category
1. | Date function: YEAR | | |
2. | Retrieve year from a date | | |
3. | Use YEAR in where clause | | |
4. | Determining the Number of Records by Day, Month, and Year | | |
5. | To find the earliest birthday within the calendar year, sort by the month and day of the birth values | | |
6. | Extract the year part of the reference date and use normal arithmetic to add 10, 20, and 40 to it | | |
7. | The following query shows two ways to determine the date for Christmas two years hence. | | |
8. | Performing Leap Year Calculations | | |
9. | Another way to compute a year's length is to compute the date of the last day of the year and pass it to DAYOF | | |
10. | Using Leap Year Tests for Month-Length Calculations | | |
11. | Extract the year from a date value by using the YEAR() function: YEAR() | | |
12. | Calculate a numerical value for the day, as it falls in the year: DAYOFYEAR() | | |
13. | Add a YEAR column type | | |
14. | %m returns the month (01-12), %d returns the day (01-31), and %Y returns the year in four digits. | | |
15. | Use the YEAR() function | | |
16. | For each player, find the player number, the year in which he or she joined the club, and the player's age gro | | |
17. | Find the player number, the year in which he or she joined the club, the town where he or she lives, and a cla | | |
18. | Get the payment number and the year of each penalty paid after 1980. | | |
19. | Get the penalties that were paid between Christmas 1982 (December 25) and New Year's Eve. | | |
20. | For each player whose number is less than 60, get the number of years between the year in which that player jo | | |
21. | Get the numbers of the players who were born in the same year as player 27. | | |
22. | Get year value from date type and compare | | |
23. | Get day name, month name and day of year | | |
24. | Get the year of a date and compare | | |
25. | Get the Year value from subquery | | |
26. | Compare the year value in where clause | | |
27. | Year value in | | |
28. | Distinct year value | | |
29. | Group by year | | |
30. | HAVING MAX(YEAR(PAYMENT_DATE)) = 1984 | | |
31. | Check year value | | |
32. | ON SCHEDULE EVERY 1 YEAR | | |
33. | WHERE clause uses only part of the date column in the comparisons: | | |
34. | Performing Date Calculations | | |
35. | Calculate an age as of the beginning 1975 for someone born on 1965-03-01. | | |
36. | How old are the Smith children today? | | |
37. | Determining Ages in Months | | |