Compare date in where clause : Date Compare Order « Date Time « SQL / MySQL

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Compare date in where clause

/*
mysql> select * from Bird;
+----------+-------+---------+------+------------+-------+
| name     | owner | species | sex  | birth      | death |
+----------+-------+---------+------+------------+-------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL  |
| RedBird  | Yin   | Car     | m    | 1979-03-30 | NULL  |
+----------+-------+---------+------+------------+-------+
2 rows in set (0.00 sec)

mysql> /*  which were born after 1998, test the birth column: */
mysql>   SELECT * FROM Bird WHERE birth > '1998-1-1';
+----------+-------+---------+------+------------+-------+
| name     | owner | species | sex  | birth      | death |
+----------+-------+---------+------+------------+-------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL  |
+----------+-------+---------+------+------------+-------+
1 row in set (0.00 sec)


*/
Drop table Bird;

CREATE TABLE Bird (
    name VARCHAR(20), 
    owner VARCHAR(20),
    species VARCHAR(20), 
    sex CHAR(1), 
    birth DATE, 
    death DATE
);
  
INSERT INTO  Bird VALUES ('BlueBird','Joe','Car','f','1999-03-30',NULL);
INSERT INTO  Bird VALUES ('RedBird','Yin','Car','m','1979-03-30',NULL);
  
select * from Bird;

  
/*  which were born after 1998, test the birth column: */ 
  SELECT * FROM Bird WHERE birth > '1998-1-1';

           
       

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