List pop([i]) : List Pop « List « Python






List pop([i])

List pop([i])
# Remove the item at the given position in the list, and return it. If no index is 
# specified, a.pop() removes and returns the last item in the list. The item is 
# also removed from the list. (The square brackets around the i in the method 
# signature denote that the parameter is optional, not that you should type square 
# brackets at that position. You will see this notation frequently in the Python 
# Library Reference.) 


a = [66.25, 333, 333, 1, 1234.5]

print a.pop(1)
print a

           
       








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