Calling fopen() with a Context Resource : fopen « File Directory « PHP






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Calling fopen() with a Context Resource

 
<?php
$url = "http://www.java2s.com/index.htm";
$options = array ("http" => array ("user_agent" => "php24-test-script", "header" => "referer: http://www.example.com/index.html\r\n" ) );
$context = stream_context_create ( $options );
$res = fopen ( $url, 'r', 0, $context ) or die ( "could not open page" );

while ( ! feof ( $res ) ) {
  print fgets ( $res, 1024 );
}

?>








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