Specify the string using logical 'OR': '|' : OR « Regular Expressions « Oracle PL / SQL






Specify the string using logical 'OR': '|'



SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','Start With Letters');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters

7 rows selected.

SQL>
SQL>
SQL> -- Alternation Operator
SQL>
SQL> -- Specify the string using logical 'OR': '|'
SQL>
SQL> SELECT description,
  2      REGEXP_INSTR(description,'r[ds]|pl')
  3  FROM testTable
  4  WHERE REGEXP_INSTR(description,'r[ds]|pl') > 0;

DESCRIPTION                    REGEXP_INSTR(DESCRIPTION,'R[DS]|PL')
------------------------------ ------------------------------------
Start With Letters                                               17

SQL>
SQL>
SQL>
SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>
           
       








Related examples in the same category

1.REGEXP_SUBSTR(description,'ird|irs'): Find all occurrences of the letter sequence 'irs' or 'ird'