REGEXP_INSTR(description,'e.e'): Find a letter and then whatever until there was another of the same letter : Wild Card « Regular Expressions « Oracle PL / SQL

1. Oracle PL / SQL
2. Regular Expressions
3. Wild Card

REGEXP_INSTR(description,'e.e'): Find a letter and then whatever until there was another of the same letter

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','eSetarte With Letterse');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    eSetarte With Letterse

7 rows selected.

SQL>
SQL> -- Find a letter and then whatever until there was another of the same letter
SQL>
SQL>
SQL> SELECT description,
  2      REGEXP_INSTR(description,'e.e') where_pattern_starts
  3  FROM testTable
  4  WHERE REGEXP_INSTR(description,'e.e') > 0;

DESCRIPTION                    WHERE_PATTERN_STARTS
------------------------------ --------------------
eSetarte With Letterse                            1

SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>
           
       

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