Match 'description' where there were no digits at all anywhere in the string



SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','Start With Letters');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters

7 rows selected.

SQL>
SQL>
SQL>
SQL> -- Match 'description' where there were no digits at all anywhere in the string we could have used
SQL> --the bracket notation, a range of numbers, and the NOT predicate.
SQL>
SQL> SELECT description
  2  FROM testTable
  3  WHERE NOT REGEXP_LIKE(description,'[0-9]');

DESCRIPTION
------------------------------
One than another
Start With Letters

SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>

Related examples in the same category

1.	Caret ('^') may be either an anchor or a negating marker
2.	Use the negating caret(not): REGEXP_LIKE(description,'[^mn]')
3.	If we wanted a non-('g' or 'p') followed by something else like an 'l'

Match 'description' where there were no digits at all anywhere in the string : NOT « Regular Expressions « Oracle PL / SQL

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