Demonstrate GROUPING in the HAVING clause
SQL> --
SQL>
SQL>
SQL> create table ord(
2 order_no integer primary key
3 ,cust_no integer
4 ,order_date date not null
5 ,total_order_price number(7,2)
6 ,deliver_date date
7 ,deliver_time varchar2(7)
8 ,payment_method varchar2(2)
9 ,emp_no number(3,0)
10 ,deliver_name varchar2(35)
11 ,gift_message varchar2(100)
12 );
Table created.
SQL>
SQL>
SQL> insert into ord(order_no,cust_no,order_date,total_order_price,deliver_date,deliver_time,payment_method,emp_no,deliver_name,gift_message)
2 values(1,1,'14-Feb-2002', 23.00, '14-Feb-2002', '12 noon', 'CA',1, null, 'Gift for wife');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time ,payment_method ,emp_no,deliver_name ,gift_message )
2 values(2,1,'14-Feb-2003', 510.98, '14-feb-2003', '5 pm', 'NY',7, 'Rose Ted', 'Happy Valentines Day to Mother');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(3, 2,'14-Feb-2004', 315.99, '14-feb-2004', '3 pm', 'VS',2, 'Ani Forest', 'Happy Valentines Day to Father');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(4, 2,'14-Feb-1999', 191.95, '14-feb-1999', '2 pm', 'NJ',2, 'O. John', 'Happy Valentines Day');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(5, 6,'4-mar-2002', 101.95, '5-mar-2002', '2:30 pm', 'MO' , 2, 'Cora', 'Happy Birthday from John');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(6, 9,'7-apr-2003', 221.95, '7-apr-2003', '3 pm', 'MA', 2, 'Sake Keith', 'Happy Birthday from Joe' );
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(7, 9,'20-jun-2004', 315.95, '21-jun-2004', '12 noon', 'BC', 2, 'Jessica Li', 'Happy Birthday from Jessica');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values (8, 12, '31-dec-1999', 135.95, '1-jan-2000', '12 noon', 'DI', 3, 'Larry', 'Happy New Year from Lawrence');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values (9, 12, '26-dec-2003', 715.95, '2-jan-2004', '12 noon', 'SK',7, 'Did', 'Happy Birthday from Nancy' );
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(10, 4, sysdate-1, 119.95, sysdate+2, '6:30 pm', 'VG',2, 'P. Jing', 'Happy Valentines Day to Jason');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message )
2 values(11, 2, sysdate, 310.00, sysdate+2, '3:30 pm', 'DC',2, 'C. Late', 'Happy Birthday Day to Jack');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message)
2 values(12, 7, sysdate-3, 121.95, sysdate-2, '1:30 pm', 'AC',2, 'W. Last', 'Happy Birthday Day to You');
1 row created.
SQL> insert into ord(order_no ,cust_no ,order_date ,total_order_price ,deliver_date ,deliver_time,payment_method ,emp_no,deliver_name ,gift_message)
2 values(13, 7, sysdate, 211.95, sysdate-4, '4:30 pm', 'CA',2, 'J. Bond', 'Thanks for hard working');
1 row created.
SQL>
SQL>
SQL> SELECT cust_no, payment_method,
2 to_char(sum(total_order_price), '999.99')
3 AS sales,
4 GROUPING(cust_no) AS c_i,
5 GROUPING(payment_method) AS p_i
6 FROM ord
7 WHERE cust_no IN (2,12)
8 GROUP BY CUBE (cust_no, payment_method)
9 HAVING GROUPING(cust_no) = 1
10 ORDER BY cust_no
11 /
CUST_NO PA SALES C_I P_I
---------- -- ------- ---------- ----------
DC 310.00 1 0
DI 135.95 1 0
NJ 191.95 1 0
SK 715.95 1 0
VS 315.99 1 0
####### 1 1
6 rows selected.
SQL>
SQL> drop table ord;
Table dropped.
SQL>
SQL> --
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