Using onMouseDown and onMouseUp Event Handlers : Mouse Event « Event « JavaScript DHTML






Using onMouseDown and onMouseUp Event Handlers

  
<HTML>
<HEAD>
<TITLE>onMouseDown and onMouseUp Event Handlers</TITLE>
<SCRIPT LANGUAGE="JavaScript">
if (document.images) {
    var RightNormImg = new Image(16,16)
    var RightUpImg = new Image(16,16)
    var RightDownImg = new Image(16,16)
    var LeftNormImg = new Image(16,16)
    var LeftUpImg = new Image(16,16)
    var LeftDownImg = new Image(16,16)
    RightNormImg.src = "http://www.java2s.com/style/logo.png"
    RightUpImg.src = "http://www.java2s.com/style/logoRed.png"
    RightDownImg.src = "http://www.java2s.com/style/logo.png"
    LeftNormImg.src = "http://www.java2s.com/style/logo.png"
    LeftUpImg.src = "http://www.java2s.com/style/logo.png"
    LeftDownImg.src = "http://www.java2s.com/style/logoRed.png"
}
function setImage(imgName, type) {
    if (document.images) {
        var imgFile = eval(imgName + type + "Img.src")
        document.images[imgName].src = imgFile
        return false
    }
}
</SCRIPT>
</HEAD>
<BODY>
<H1>onMouseDown and onMouseUp Event Handlers</H1>
<HR>
<P>Roll atop and click on the buttons to see how the link event handlers swap
 images:</P>
<CENTER>
<A HREF="javascript:void(0)"
    onMouseOver="return setImage('Left','Up')"
    onMouseDown="return setImage('Left','Down')"

onMouseUp="return setImage('Left','Up')"
    onMouseOut="return setImage('Left','Norm')"
>
<IMG NAME="Left" SRC="LeftNorm.gif" HEIGHT=16 WIDTH=16 BORDER=0></A>
&nbsp;&nbsp;
<A HREF="javascript:void(0)" 
    onMouseOver="return setImage('Right','Up')"
    onMouseDown="return setImage('Right','Down')"
    onMouseUp="return setImage('Right','Up')"
    onMouseOut="return setImage('Right','Norm')"
>
<IMG NAME="Right" SRC="RightNorm.gif" HEIGHT=16 WIDTH=16 BORDER=0></A>
</CENTER>
</BODY>
</HTML>

           
         
    
  








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