Determine whether the supplied string represents a well-formed fully-qualified Java classname. : Identifier « Reflection « Java






Determine whether the supplied string represents a well-formed fully-qualified Java classname.

  
/*
 * JBoss DNA (http://www.jboss.org/dna)
 * See the COPYRIGHT.txt file distributed with this work for information
 * regarding copyright ownership.  Some portions may be licensed
 * to Red Hat, Inc. under one or more contributor license agreements.
 * See the AUTHORS.txt file in the distribution for a full listing of 
 * individual contributors. 
 *
 * JBoss DNA is free software. Unless otherwise indicated, all code in JBoss DNA
 * is licensed to you under the terms of the GNU Lesser General Public License as
 * published by the Free Software Foundation; either version 2.1 of
 * the License, or (at your option) any later version.
 *
 * JBoss DNA is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
 * Lesser General Public License for more details.
 *
 * You should have received a copy of the GNU Lesser General Public
 * License along with this software; if not, write to the Free
 * Software Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA
 * 02110-1301 USA, or see the FSF site: http://www.fsf.org.
 */

import java.text.CharacterIterator;
import java.text.StringCharacterIterator;


public class Utils {

  /**
   * Determine whether the supplied string represents a well-formed fully-qualified Java classname. This utility method enforces
   * no conventions (e.g., packages are all lowercase) nor checks whether the class is available on the classpath.
   * 
   * @param classname
   * @return true if the string is a fully-qualified class name
   */
  public static boolean isFullyQualifiedClassname( String classname ) {
      if (classname == null) return false;
      String[] parts = classname.split("[\\.]");
      if (parts.length == 0) return false;
      for (String part : parts) {
          CharacterIterator iter = new StringCharacterIterator(part);
          // Check first character (there should at least be one character for each part) ...
          char c = iter.first();
          if (c == CharacterIterator.DONE) return false;
          if (!Character.isJavaIdentifierStart(c) && !Character.isIdentifierIgnorable(c)) return false;
          c = iter.next();
          // Check the remaining characters, if there are any ...
          while (c != CharacterIterator.DONE) {
              if (!Character.isJavaIdentifierPart(c) && !Character.isIdentifierIgnorable(c)) return false;
              c = iter.next();
          }
      }
      return true;
  }

}

   
    
  








Related examples in the same category

1.Is Java Identifier and get Java Identifier
2.Escape Java Literal
3.To Identifier String
4.Check whether the given String is a valid identifier according to the Java Language specifications.
5.Determines if the specified string is permissible as a Java identifier.