how sorted search results can be obtained using SortControl API : Search « JNDI LDAP « Java






how sorted search results can be obtained using SortControl API

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import java.io.IOException;
import java.util.Hashtable;

import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
import javax.naming.ldap.Control;
import javax.naming.ldap.HasControls;
import javax.naming.ldap.InitialLdapContext;
import javax.naming.ldap.LdapContext;
import javax.naming.ldap.SortControl;
import javax.naming.ldap.SortResponseControl;

/**
 * Shows how sorted search results can be obtained using SortControl API
 */
class SortedResults {

  public static void main(String[] args) throws IOException {

    // Set up environment for creating initial context
    Hashtable<String, Object> env = new Hashtable<String, Object>(11);
    env
        .put(Context.INITIAL_CONTEXT_FACTORY,
            "com.sun.jndi.ldap.LdapCtxFactory");
    env.put(Context.PROVIDER_URL,
        "ldap://localhost:389/ou=People,o=JNDITutorial");

    try {
      // Create initial context with no connection request controls
      LdapContext ctx = new InitialLdapContext(env, null);

      // Create a sort control that sorts based on CN
      String sortKey = "cn";
      ctx.setRequestControls(new Control[] { new SortControl(sortKey,
          Control.CRITICAL) });

      // Perform a search
      NamingEnumeration results = ctx.search("", "(objectclass=*)",
          new SearchControls());

      // Iterate over search results
      System.out.println("---->sort by cn");
      while (results != null && results.hasMore()) {
        // Display an entry
        SearchResult entry = (SearchResult) results.next();
        System.out.println(entry.getName());

        // Handle the entry's response controls (if any)
        if (entry instanceof HasControls) {
          // ((HasControls)entry).getControls();
        }
      }
      // Examine the sort control response
      Control[] controls = ctx.getResponseControls();
      if (controls != null) {
        for (int i = 0; i < controls.length; i++) {
          if (controls[i] instanceof SortResponseControl) {
            SortResponseControl src = (SortResponseControl) controls[i];
            if (!src.isSorted()) {
              throw src.getException();
            }
          } else {
            // Handle other response controls (if any)
          }
        }
      }

      // Close when no longer needed
      ctx.close();
    } catch (NamingException e) {
      e.printStackTrace();
    }
  }
}

 








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