Java generic: Hierarchy argument : Generic Parameter « Generics « Java






Java generic: Hierarchy argument

Java generic: Hierarchy argument
 
class Stats<T extends Number> {
  T[] nums;

  Stats(T[] o) {
    nums = o;
  }

  double average() {
    double sum = 0.0;

    for (int i = 0; i < nums.length; i++)
      sum += nums[i].doubleValue();

    return sum / nums.length;
  }
}

public class BoundsDemo {
  public static void main(String args[]) {
    Integer inums[] = { 1, 2, 3, 4, 5 };
    Stats<Integer> iob = new Stats<Integer>(inums);
    double v = iob.average();
    System.out.println("iob average is " + v);

    Double dnums[] = { 1.1, 2.2, 3.3, 4.4, 5.5 };
    Stats<Double> dob = new Stats<Double>(dnums);
    double w = dob.average();
    System.out.println("dob average is " + w);

  }
}
          
         
  








Related examples in the same category

1.A simple generic class with two type parameters: T and V.A simple generic class with two type parameters: T and V.
2.Boxing Generic Example
3.Demonstrate a raw generic type. Demonstrate a raw generic type.
4.T is a type parameter that will be replaced by a real type when an object of type Gen is created.
5.Create a generic class that can compute the average of an array of numbers of any given type.
6.the type argument for T must be either Number, or a class derived from Number.
7.Demonstrate a raw type.
8.A subclass can add its own type parameters.
9.Compare two generic parameters
10.Default implementation of {@link java.lang.reflect.ParameterizedType}
11.Get the Generic definition from a class for given class with given index.