How to deal with the console parameters : Console « Development Class « Java






How to deal with the console parameters

How to deal with the console parameters
  
public class ConsoleArguments {
  public static void main(String[] args) {
    if (args.length == 0) {
      System.out.println("No arguments");
    } else {
      System.out.println("Arguments:");
      for (int i = 0; i < args.length; i++) {
        System.out.println(args[i]);
      }
    }
  }
}
           
         
    
  








Related examples in the same category

1.Turn System.out into a PrintWriterTurn System.out into a PrintWriter
2.Output to standard output and standard error; and input from standard input.Output to standard output and standard error; and input from standard input.
3.VarArgsDemo - show 1.5 variable argumentsVarArgsDemo - show 1.5 variable arguments
4.How to read from standard inputHow to read from standard input
5.Read input from consoleRead input from console
6.Command line input
7.Read an int from Standard Input
8.Read an int from Standard Input, using 1.5
9.SimpleCalc -- simple calculator using 1.5 java.util.Scanner
10.Show use of Argv to get an integer value from command lineShow use of Argv to get an integer value from command line
11.Java program to calculate the area of a circleJava program to calculate the area of a circle
12.Java program to demonstrate menu selectionJava program to demonstrate menu selection
13.Utility class for printing aligned columns of text
14.Processing the command line
15.A representation of the command line arguments passed to a Java class' main(String[]) method
16.Helper class for storing long command lines inside temporary file.
17.CommandLine Parser
18.This parses command line arguments optimized for ease of programmer use.
19.Console read and write Utils