Demonstrate findInLine()
/** *Output: 28 */ import java.util.Scanner; public class MainClass { public static void main(String args[]) { String instr = "Name: Joe Age: 28 ID: 77"; Scanner conin = new Scanner(instr); conin.findInLine("Age:"); // find Age if (conin.hasNext()) System.out.println(conin.next()); else System.out.println("Error!"); } }