Use set_union to union two lists
#include <algorithm>
#include <functional>
#include <iomanip>
#include <iostream>
#include <list>
#include <string>
#include <vector>
using namespace std;
class PC
{
public:
enum part { keyboard, mouse, monitor };
PC( part a_part = PC::keyboard, int id = 0 );
bool operator<( const PC& rhs ) const;
void print() const;
private:
part part_;
int id_;
};
inline
PC::PC( part a_part, int id ) : part_( a_part ), id_( id ){}
inline bool PC::operator<( const PC& rhs ) const{
return id_ < rhs.id_;
}
void PC::print() const {
string component;
if( part_ == keyboard )
component = "keyboard";
else if( part_ == mouse )
component = "mouse";
else
component = "monitor";
cout << "ID: " << setw( 8 ) << left << id_ << " PC: " << component << endl;
}
int main( )
{
list<PC> listA;
listA.push_back( PC( PC::keyboard, 3 ) );
listA.push_back( PC( PC::mouse, 1 ) );
listA.push_back( PC( PC::monitor, 9 ) );
listA.push_back( PC( PC::keyboard, 2 ) );
listA.push_back( PC( PC::monitor, 8 ) );
list<PC> inspector_B( listA );
inspector_B.front() = PC( PC::mouse, 6 );
inspector_B.back() = PC( PC::monitor, 1 );
// must sort before using set algorithms
listA.sort();
inspector_B.sort();
for_each( listA.begin(), listA.end(),mem_fun_ref( &PC::print ) );
for_each( inspector_B.begin(), inspector_B.end(),mem_fun_ref( &PC::print ) );
vector<PC> result;
// make vector large enough to hold all inspected parts
result.resize( listA.size() + inspector_B.size() );
vector<PC>::iterator the_end = set_union( listA.begin(), listA.end(),inspector_B.begin(), inspector_B.end(), result.begin() );
for_each( result.begin(), the_end, mem_fun_ref( &PC::print ) );
}
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