Use unique_copy to print elements without consecutive entries that differ by one : unique copy « STL Algorithms Modifying sequence operations « C++

1. C++
2. STL Algorithms Modifying sequence operations
3. unique copy

Use unique_copy to print elements without consecutive entries that differ by one

 
 
    
    
/* The following code example is taken from the book
 * "The C++ Standard Library - A Tutorial and Reference"
 * by Nicolai M. Josuttis, Addison-Wesley, 1999
 *
 * (C) Copyright Nicolai M. Josuttis 1999.
 * Permission to copy, use, modify, sell and distribute this software
 * is granted provided this copyright notice appears in all copies.
 * This software is provided "as is" without express or implied
 * warranty, and with no claim as to its suitability for any purpose.
 */

#include <iostream>
#include <vector>
#include <deque>
#include <list>
#include <set>
#include <map>
#include <string>
#include <algorithm>
#include <iterator>
#include <functional>
#include <numeric>

/* PRINT_ELEMENTS()
 * - prints optional C-string optcstr followed by
 * - all elements of the collection coll
 * - separated by spaces
 */
template <class T>
inline void PRINT_ELEMENTS (const T& coll, const char* optcstr="")
{
    typename T::const_iterator pos;

    std::cout << optcstr;
    for (pos=coll.begin(); pos!=coll.end(); ++pos) {
        std::cout << *pos << ' ';
    }
    std::cout << std::endl;
}

/* INSERT_ELEMENTS (collection, first, last)
 * - fill values from first to last into the collection
 * - NOTE: NO half-open range
 */
template <class T>
inline void INSERT_ELEMENTS (T& coll, int first, int last)
{
    for (int i=first; i<=last; ++i) {
        coll.insert(coll.end(),i);
    }
}


using namespace std;

bool differenceOne (int elem1, int elem2)
{
    return elem1 + 1 == elem2 || elem1 - 1 == elem2;
}

int main()
{
    // source data
    int source[] = { 1, 4, 4, 6, 1, 2, 2, 3, 1, 6, 6, 6, 5, 7,
                      5, 4, 4 };
    int sourceNum = sizeof(source)/sizeof(source[0]);

    // initialize coll with elements from source
    list<int> coll;
    copy(source, source+sourceNum,      // source
         back_inserter(coll));          // destination
    PRINT_ELEMENTS(coll);

    // print elements without consecutive entries that differ by one
    unique_copy(coll.begin(), coll.end(),         // source
                ostream_iterator<int>(cout," "),  // destination
                differenceOne);                   // duplicates criterion
    cout << endl;
}

/* 
1 4 4 6 1 2 2 3 1 6 6 6 5 7 5 4 4
1 4 4 6 1 3 1 6 6 6 4 4

 */        
  

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