Generating digit numbers of equally total digits
Code submitted by Kean Peng Tan (kptan1980 at gmail.com)
//generate number version I
//this program is generating digit number
//numbers of equally total digits
//which means digit1+digit2+digit3+digit4
//is equally same shall be generated
//read and write a text file
#include <iostream>
#include <fstream>
#include <iostream>
using namespace std;
main()
{
//reading a file
ofstream out("c:\\generate.txt"); // output, normal file
if(!out) {
cout << "Cannot open test file.\n";
return 1;
}
//variables
int input=25; //modified here
int temp[3];
temp[0]=0;
temp[1]=0;
temp[2]=0;
temp[3]=0;
//repetitive loop
int total=0;
int sum=0; // initial sum
int row=0; // initial row
int p1,p2,p3,p4;
p1=temp[0]; //MSB
p2=temp[1];
p3=temp[2];
p4=temp[3];
for(p1=0;p1<10;p1++){
if(p2==10){
p2=0;}
for(p2=0;p2<10;p2++){
if(p3==10){
p3=0;}
for(p3=0;p3<10;p3++){
if(p4==10){
p4=0;}
for(p4=0;p4<10;p4++)
{
//4th digit
//determine loop
sum=p1+p2+p3+p4;
if(sum==input)
{
out << p1 << p2 << p3 << p4 << " ";
total++;
row=total;
if(row%10==0)
{
out << endl;
}
} //end sum if
} //end inner loop p4
} //end inner loop p3
} //end inner loop p2
} //end inner loop p1
out << "The sum of outputs is equal to " << input << endl;
out << "Total: " << total << endl; // display in file
out.close();
cout << "Total: " << total << endl;
cout << "success!" << endl;
system("pause");
return 0;
}// end main
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