Allocate memory for int array


#include <stdio.h>
#include <malloc.h>

main() {
    int  *base; 
    int i;    
    int j;
    int cnt=0;
    int sum=0;
    
    printf("how many integers you have to store \n");  
    scanf("%d",&cnt); 
    base = (int *)malloc(cnt * sizeof(int)); 
    printf("the base of allocation is %16lu \n",base);
    
    if(!base) 
        printf("unable to allocate size \n");
    else {    
      for(j = 0; j < cnt; j++)
          *(base+j)=5;
    }
    sum = 0;
     
    for(j = 0; j < cnt; j++)
      sum = sum + *(base+j);
    printf("total sum is %d\n",sum);
    
    free(base);
    
    printf("addr of allocation is %16lu \n",base);
    base = (int *)malloc(cnt * sizeof(int));
    printf("the base of allocation is %16lu \n",base);
    base = (int *)malloc(cnt * sizeof(int));
    printf("the base of allocation is %16lu \n",base);
    base = (int *)calloc(10,2);  
    printf("the base of allocation is %16lu \n",base);
}

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Allocate memory for int array : Array Int « Data Type « C / ANSI-C

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