super and overridden method
To access the superclass version of an overridden function, you can do so by using super.
class Base {
int i;
Base(int a) {
i = a;
}
void show() {
System.out.println("i: " + i);
}
}
class SubClass extends Base {
int k;
SubClass(int a, int c) {
super(a);
k = c;
}
void show() {
super.show(); // this calls A's show()
System.out.println("k: " + k);
}
}
public class Main {
public static void main(String[] argv) {
SubClass sub = new SubClass(1, 2);
sub.show();
}
}
The following output will be generated if you run the code above:
i: 1
k: 2